Identify number with positive index and with integral base.
$2^{- 3}, 2^{- 5}, \frac{1}{3^{4}}, {- 2}^{3}$

2^{- 3}

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2^{- 5}

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\frac{1}{3^{4}}

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{- 2}^{3}

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Solution

The correct option is B ${- 2}^{3}$
$\Rightarrow$ $2^{- 3}, 2^{- 5}, \frac{1}{3^{4}}, - 2^{3}$
$\Rightarrow$ In the given numbers we have to find number with positive index and with integral base.
$\Rightarrow$ $- 2^{3}$ number has positive index $3$ and integral base $- 2$ .

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Similar questions

(\frac{3}{4} + \frac{- 2}{5}) + \frac{- 7}{10} = \frac{3}{4} + (\frac{- 2}{5} + \frac{- 7}{10})

(\frac{- 7}{11} + \frac{2}{- 5}) + \frac{- 13}{22} = \frac{- 7}{11} + (\frac{2}{- 5} + \frac{- 13}{22})

- 1 + (\frac{- 2}{3} + \frac{- 3}{4}) = (- 1 + \frac{- 2}{3}) + \frac{- 3}{4}

\frac{2}{3} \times (\frac{5}{7} \times \frac{3}{4}) :

\frac{2}{3} \times (\frac{5}{7} \times \frac{3}{4}) = \frac{2}{3} \times (\frac{3}{4} \times \frac{5}{7})

\frac{2}{3} \times (\frac{3}{4} \times \frac{5}{7}) = (\frac{2}{3} \times \frac{3}{4}) \times \frac{5}{7}

\frac{1}{2} \times \frac{5}{7} = \frac{5}{14}

Simplify the following :
$[{(\frac{- 3}{4})}^{3} - {(\frac{- 5}{2})}^{3}] \times {(- \frac{2}{3})}^{4}$ .

2 (34 + 66) - (23 + 77) =

2, 7, 14, 23, 34, ?

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