Identify oxidant and reductant in the following redox reactions.
${2 K}_{2} M n O_{4} + {C l}_{2} ⟶ 2 K C l + 2 K M n O_{4}$

Oxidant:

{C l}_{2}

; Reductant:

K C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Oxidant:

{C l}_{2}

; Reductant:

K_{2} M n O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Oxidant:

K_{2} M n O_{4}

; Reductant:

{C l}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Oxidant: ${C l}_{2}$ ; Reductant: $K_{2} M n O_{4}$
Here, in this reaction $C l_{2}$ is the oxidant and $K_{2} M n O_{4}$ is reductant.
Because the oxidation state of $C l_{2}$ changes $0 \to - 1$ , and decrease in oxidation state means it is reducing and self reducing is always oxidant for other.
And $M n$ O.S. is changing $+ 6$ to $+ 7$ , so $M n$ is increasing oxidation state so oxidising and as self oxidising is reductant for other. So this reductant.

Suggest Corrections

Similar questions

C a + C l_{2} \to C a C l_{2}

C l O_{3}^{-} + C l^{-} \to C l_{2} + C l O_{2}

H_{2} S (g) + C l_{2} \to 2 H C l (g) + S (s)

K_{2} M n O_{4} + C l_{2} ⟶ 2 K C l + 2 K M n O_{4}

2

C l_{2}

2

K_{2} M n O_{4}

K M n O_{4}

Join BYJU'S Learning Program