Question

Identify the algebraic pattern and find the nth term in the following $0,6,16,30,48$

Answer 1

$2(1{)}^2-2=0$
$2(2{)}^2-2=6$
$2(3{)}^2-2=16$
$2(4{)}^2-2=30$
$2(5{)}^2-2=48$
$\therefore$ hence, the nth term can be represented as $2n^2-2$