Question

Identify the anion present in the salt on the basis of the reaction given below

When a freshly prepared solution of ferrous sulphate is added to a salt solution and concentrated sulphuric acid is gently poured from the side of the test tube, a brown ring is formed.

• A. Nitrate
• B. Chloride
• C. Sulphide
• D. Oxide
• E. Carbonate
• F. Sulphite
• G. Bromide
• H. Iodide

Answer 1

Answer: (A)

Nitrate
The identification and conformation test of nitrate ion $N{O}_3^{-}$ using concentrated sulphuric acid and freshly prepared ferrous sulphate , is called as 'Brown Ring Test. In a test tube take the $N{O}_3^{-1}$ containing sample .Then add concentrated sulphuric acid dropwise with gentle shaking and then heat it shortly using Bunsen burner & add freshly prepared greenish $FeS{O}_4$. Then, we can observe a brown ring formed in that test tube due to the formation of brown colored $\left[Fe\right(H_{2}O{)}_5\left(NO\right)]S{O}_4$