Identify the balanced chemical reaction between copper and sulphuric acid.

2 C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + 2 C u S O_{4}

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C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + C u S O_{4}

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C u + H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + C u S O_{4}

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3 C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + H_{2} O + 3 C u S O_{4}

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Solution

The correct option is B $C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + C u S O_{4}$
$C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + C u S O_{4}$

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Similar questions

C u + 2 H_{2} {S O}_{4} ⟶ C u {S O}_{4} + {S O}_{2} + 2 H_{2} O

2 H_{2} {S O}_{4} 830^{o} C - --- \to {2 S O}_{x} + 2 H_{2} O + O_{2}

I_{2} + {S O}_{2} + {2 H}_{2} O 120^{o} C - -- \to z H I + H_{2} {S O}_{4}

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x, y

z

C u + H_{2} {S O}_{4} - \to C u S O_{4} + {S O}_{2} ↑ + H_{2} O

F e + + H_{2} O - \to {F e}_{3} O_{4} + H_{2} ↑

{C H}_{4} + O_{2} \to C O_{2} + H_{2} O

What is the balanced form of the equation written below?

$C u + H_{2} S O_{4} \to C u S O_{4} + S O_{2} + H_{2} O$

2 H_{2} S + S O_{2} \to 2 H_{2} O + 3 S

S O_{2}

H_{2} S

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