Identify the binary mixture(s) that can be separated into the individual compounds, by differential extraction, as shown in the given scheme?

C_{6} H_{5} O H

and

C_{6} H_{5} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} C O O H

and

C_{6} H_{5} {C H}_{2} O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} {C H}_{2} O H

and

C_{6} H_{5} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} {C H}_{2} O H

and

C_{6} H_{5} C O O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
B $C_{6} H_{5} C O O H$ and $C_{6} H_{5} {C H}_{2} O H$
D $C_{6} H_{5} {C H}_{2} O H$ and $C_{6} H_{5} C O O H$
(A) Both are soluble in NaOH, hence inseparable.
(B) Only benzoic acid ( $C_{6} H_{5} C O O H$ ) is soluble in NaOH and, while benzyl alcohol ( $C_{6} H_{5} C H_{2} O H$ )
is not. Hence, separable.
(C) Although NaOH can enable separation between benzyl alcohol ( $C_{6} H_{5} C H_{2} O H$ ) and phenol ( $C_{6} H_{5} O H$ ) as
only the later is soluble in NaOH. However, in $N a H C O_{3}$ , both are insoluble. Hence, inseparable.
(D) α -phenylacetic acid ( $C_{6} H_{5} C H_{2} C O O H$ )
is soluble in NaOH and $N a H C O_{3}$ . While benzyl alcohol
( $C_{6} H_{5} C H_{2} O H$ ) is not. Hence, separable.
Hence: The answer is both option(B) and option(D).

Suggest Corrections

Similar questions

C_{6} H_{5} {C O N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H C H}_{3}

A : 2 C_{6} H_{5} C H O + K O H ⟶ C_{6} H_{5} C O O K + C_{6} H_{5} {C H}_{2} O H

B : 3 {C l}_{2} + 6 K O H ⟶ 5 K C l + K C l O_{3} + 3 H_{2} O

2 C_{6} H_{5} C H O + {O H}^{-} ⟶ C_{6} H_{5} C O O^{-} + C_{6} H_{5} {C H}_{2} O H

C_{6} H_{5} C O O H + {C H}_{3} M g I \to

C_{6} H_{5} {N H}_{2}

C_{6} H_{5} {N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H}_{2}

Join BYJU'S Learning Program