Identify the compound $D$ .

Z n S_{2}

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Z n C O_{3}

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C a S

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Z n S

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Solution

The correct option is C $Z n S$
The solid that is yellow when hot and white when cold is zinc oxide. The gas is carbon dioxide,from its behaviour towards lime water. In alkaline medium, zinc sulphide is precipitated by hydrogen sulphide gas. The precipitate of zinc hydroxide is soluble in excess of sodium hydroxide due to the formation of sodium zincate.
$A Δ - \to Z n O + B$
$Z n C O_{3} Δ - \to Z n O + C O_{2}$
$Z n O + 2 H C l ⟶ Z n C l_{2} + H_{2} O$
$2 Z n C l_{2} + K_{4} [F e (C N)_{6}] ⟶ 4 K C l + Z n_{2} [F e (C N)_{6}] ↓$
$\begin{matrix} C O_{2} & + & C a (O H)_{2} & ⟶ & H_{2} O & + & C a C O_{3} ↓ M i l k i n e s s \end{matrix}$
$\begin{matrix} C a C O_{3} & + & C O_{2} & + & H_{2} O & ⟶ & C a (H C O_{3})_{2} S o l u b l e \end{matrix}$
$Z n C O_{3} + H C l ⟶ C O_{2} ↑ + Z n C l_{2}$
$Z n C l_{2} + H_{2} S N H_{4} O H - ---- \to 2 H C l + Z n S ↓$
$Z n C l_{2} + N a O H ⟶ Z n (O H)_{2} ↓ + 2 N a C l$
$Z n (O H)_{2} N a O H - --- \to N a Z n O_{2} (s o l u b l e)$

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