Identify the compound in which the total number of constituent atoms present in a molecule is even:

ferric oxide

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calcium hydrogen sulphide

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calcium nitrate

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sodium nitrate

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Solution

The correct option is B calcium hydrogen sulphide
The number of constituents in each compound is:
Ferric oxide: $F e_{2} O_{3}$ $=$ 5
Calcium hydrogen sulphide: $C a H_{2} S$ $=$ 4
Calcium nitrate: $C a (N O_{3})_{2}$ $=$ 9
Sodium nitrate: $N a N O_{3}$ $=$ 5

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