Identify the compounds A, B, and C in the following reaction.
$C H_{3} - B r M g / e r a r \to (A) (i) C O_{2} - ---- \to (i i) W a r e (B) C H_{2} O H / H^{+} - ------- \to △ (C)$

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Solution

Complet chemial conversation can be done as
Hence, $A = C H_{3} M g B r, B = C H_{3} C O O H, C = C H_{3} - C - O_{C} H_{3}$

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A

B

C H_{3} - C H_{3} B \leftarrow ---- - C H_{3} C O O H A - ---- \to C H_{3} C H_{2} O H

A, B, C

D

P {C l}_{5} + S O_{2} ⟶ A + B

A + C H_{3} C O O H ⟶ C + S O_{2} + H C l

2 C + {(C H_{3})}_{2} C d ⟶ D + C d {C l}_{2}

C H_{3} - C H_{2} - B r + A g C N Δ \to A \frac{N a}{C_{2} H_{5} O H} \to B

D

C H_{3} - C H (C H_{3}) - C H_{2} - C H_{2} - B r a l c . K O H - ----- \to Δ A (i) C o n c . H_{2} S O_{4} - --------- \to (i i) H_{2} O / Δ B Major product + C Minor product

B H I / Δ - --- \to - H_{2} O D Major product + E Minor product

C H_{3} - C H_{2} - C H_{2} - C H O ¯ ¯¯ ¯ O H - - \to A - H_{2} O - --- \to B H_{2} / R a n e y N i - ------- \to C

C_{6} H_{5} - C H O + C H_{3} - C H_{2} C O - C H_{3} ¯ ¯¯ ¯ O H - - \to A - H_{2} O - --- \to B I_{2} / N a O H - ----- \to C

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