Identify the compounds $(X), (Y)$ and $(Z)$ by making an appropriate choice. $C H_{3} B r M g / e t h e r - ----- \to X (i) C O_{2} - ---- \to (i i) w a t e r Y C H_{3} O H, H^{+} - ------ \to Δ Z$

(X) = C H_{3} M g B r (Y) = C H_{3} C O O H, (Z) = C H_{3} C O O C H_{3}

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(X) = C H_{3} C H_{2} B r, (Y) = C H_{3} C H_{2} O H, (Z) = C H_{3} C H_{2} C H_{2} C H_{3}

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(X) = C H_{3} C H_{2} M g B r, (Y) = C H_{3} C H_{2} C O O H, (Z) = C H_{3} C H_{2} C O C H_{3}

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(X) = C H_{3} C O O H, (Y) = C H_{3} C H_{2} C O C H_{3}, (Z) = C H_{3} C O O C H_{3}

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Solution

The correct option is A $(X) = C H_{3} M g B r (Y) = C H_{3} C O O H, (Z) = C H_{3} C O O C H_{3}$
Hence, option $A$ is correct.

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