Identify the condition necessary for the conversion of $B$ and $C$ .

B -

hot and conc.

N a O H

C -

cold and dil.

N a O H

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B -

conc.

N a O H

C -

per chloric acid

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B -

per chloric acid,

C -

sodium chloride

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B -

sodium chloride,

C -

conc. NaOH

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Solution

The correct option is A $B -$ hot and conc. $N a O H$ , $C -$ cold and dil. $N a O H$
In presence of hot and concentrated $N a O H$ :
$6 N a O H + C l_{2} ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O$
In the presence of cold and diluted $N a O H$ :
$2 N a O H + C l_{2} ⟶ N a C l + N a C l O + H_{2} O$

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