Identify the correct combination reaction of two compounds to form a new product

H_{2} + C l_{2} \to 2 H C l

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2 C O + O_{2} \to 2 C O_{2}

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C a O + H_{2} O \to C a (O H)_{2}

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N H_{3} + H C l \to N H_{4} C l

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Solution

The correct options are
A $H_{2} + C l_{2} \to 2 H C l$
B $C a O + H_{2} O \to C a (O H)_{2}$
C $2 C O + O_{2} \to 2 C O_{2}$
D $N H_{3} + H C l \to N H_{4} C l$
A combination reaction is a reaction where two or more elements or compounds combine to form a single compound (product). Such reactions may be represented by equations of the following form: X + Y $⟶$ XY.
Example - $C a O + H_{2} O ⟶ C a (O H)_{2}$
$N H_{3} + H C l ⟶ N H_{4} C l$
So all of the above options are correct.

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Similar questions

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} ↑ + H_{2} O

N a + H_{2} O \to N a O H + H_{2} ↑

(N H_{4})_{2} S O_{4} + C a (O H)_{2} \to C a S O_{4} + N H_{3} ↑ + H_{2} O

H g (N O_{3})_{2} \to H g + N O_{2} ↑ + O_{2} ↑

P b_{3} O_{4} + H C l \to P b C l_{2} + C l_{2} ↑ + H_{2} O

What is the product of the reaction of $H_{2} O_{2}$ with $C l_{2}$ ?

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

What type of reactions are represented by the following equations ?

(i) $C a C O_{3} ⟶ C a O + C O_{2}$

(ii) $C a O + H_{2} O ⟶ C a (O H)_{2}$

(iii) $2 F e S O_{4} ⟶ F e_{2} O_{3} + S O_{2} + S O_{3}$

(iv) $N H_{4} C l ⟶ N H_{3} + H C l$

(v) $2 C a + O_{2} ⟶ 2 C a O$

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