Identify the correct order of acidic strength of $C O_{2}$ , $C u O$ , $C a O$ , and $H_{2} O$ :

$C a O < C u O < H_{2} O < C O_{2}$

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$H_{2} O < C u O < C a O < C O_{2}$

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$C a O < H_{2} O < C u O < C O_{2}$

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$H_{2} O < C O_{2} < C a O < C u O$

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Solution

The correct option is A
$C a O < C u O < H_{2} O < C O_{2}$

Clearly, water is neutral. CuO is mildly basic whereas CaO is much more basic than Copper (II) oxide.

$C O_{2}$ is acidic. Hence, $C a O < C u O < H_{2} O < C O_{2}$

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