Question

Identify the correct order of reactivity in electrophillic substitution reactions of the following compounds

• A. $1>2>3>4$
• B. $4>3>2>1$
• C. $2>1>3>4$
• D. $2>3>1>4$

Answer 1

The correct option is C $2>1>3>4$

More activated group attracts electrophile easily.

The $-N{O}_2$ group is electron withdrawing group, so it deactivates the benzene ring largely.
$-Cl$ atom is also deactivates the benzene ring largely but this deactivation is lower to $-N{O}_2$ group.
While $-C{H}_3$ group activates the benzene ring. Hence, on the basis of activation and deactivation they have the following order of electrophillic attraction.