Identify the correct order of velocity (speed) of sound. Given,
$v_{O_{2}} =$ velocity of sound in $O_{2}$ gas
$v_{N_{2}} =$ velocity of sound in $N_{2}$ gas
$v_{H_{2}} =$ velocity of sound in $H_{2}$ gas
$v_{C l_{2}} =$ velocity of sound in $C l_{2}$ gas.

v_{H_{2}} > v_{N_{2}} > v_{O_{2}} > v_{C l_{2}}

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v_{H_{2}} = v_{N_{2}} = v_{O_{2}} = v_{C l_{2}}

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v_{C l_{2}} > v_{O_{2}} > v_{N_{2}} > v_{H_{2}}

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v_{N_{2}} = v_{C l_{2}} > v_{O_{2}} > v_{H_{2}}

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Solution

The correct option is A $v_{H_{2}} > v_{N_{2}} > v_{O_{2}} > v_{C l_{2}}$
Velocity of sound in gas is inversely to square-root of molecular mass.
So correct decreasing order of velocities would be
$v_{H} > v_{N_{2}} > v_{O_{2}} > v_{c l_{2}}$
Option A is correct.

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