Identify the correct order of wavelength of light absorbed for the following complex ions.

$[C o (H_{2} O)_{6}]^{3 +}; C o (C N)_{6}]^{3 -}; [C o (I)_{6}]^{3 -}; [C o (e n)_{3}]^{3 +}$
I II III IV

III > I > IV > II

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II > IV > I > III

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III > I > II > IV

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I > III > IV > II

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Solution

The correct option is A III > I > IV > II
Stronger is the ligand, greater will be the crystal field splitting and lower will be the wavelength of light absorbed.

The increasing order of the crystal field splitting (as per the ligand strength according to spectrochemical series) is $C N^{-} > e n > H_{2} O > I^{-}$ .

And the order of wavelength absorbed by the respective ligands is $C N^{-} < e n < H_{2} O < I^{-}$ .

Hence, the decreasing order of the wavelengths of light absorbed by the complex ions is $I I I > I > I V > I I$ .

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Similar questions

\begin{matrix} [C o (H_{2} O)_{6}]^{3 +}; & [C o (C N)_{6}]^{3 -}; & [C o (I)_{6}]^{3 -}; & [C o (e n)_{3}]^{3 +} I & I I & I I I & I V \end{matrix}

K_{2} C O_{3} (I), M g C O_{3} (I I), C a C O_{3} (I I I), B e C O_{3} (I V)

+ I

- C H_{3}

- C D_{3}

- C T_{3}

- C H D_{2}

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

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