Identify the correct representation of reaction occurring during chloralkali process.

2 N a C l (l) + 2 H_{2} O (l) \to 2 N a O H (l) + C l_{2} (g) + H_{2} (g)

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2 N a C l (a q) + 2 H_{2} O (a q) \to 2 N a O H (a q) + C l_{2} (g) + H_{2} (g)

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2 N a C l (a q) + 2 H_{2} O (l) \to 2 N a O H (a q) + C l_{2} (a q) + H_{2} (a q)

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2 N a C l (a q) + 2 H_{2} O (l) \to 2 N a O H (a q) + C l_{2} (g) + H_{2} (g)

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Solution

The correct option is D $2 N a C l (a q) + 2 H_{2} O (l) \to 2 N a O H (a q) + C l_{2} (g) + H_{2} (g)$
Sodium chloride in water is a brine solution which gives sodium hydroxide in aqueous solution and hydrogen and chlorine gases. It is known as chloralkali process. It is an industrial process for the electyrolysis of sodium chloride. It is the technology which is used to produce chlorine and caustic soda(sodium hydroxide) on commercial scale.

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Similar questions

Q. Question 30.
Identify the correct representation of reaction occurring during chloralkali process.
(a)

2 NaCl(l) + 2 H_{2} O(l) \to 2 NaOH(l) + {Cl}_{2} (g) + H_{2} (g)

(b)

2 NaCl(aq) + 2 H_{2} O(aq) \to 2 NaOH(aq) + {Cl}_{2} (g) + H_{2} (g)

(c)

2 NaCl(aq) + 2 H_{2} O(l) \to 2 NaOH(aq) + {Cl}_{2} (aq) + H_{2} (aq)

(d)

2 NaCl(aq) + 2 H_{2} O(l) \to 2 NaOH(aq) + {Cl}_{2} (g) + H_{2} (g)

NaOH is prepared industrially by electrolysis of brine (NaCl). $2 N a C l (a q) + 2 H_{2} O (l) \to C l_{2} (g) + 2 N a O H (a q) + H_{2} (g)$ . The name of this process is Soda-lime process. If true enter 1, else enter 0.

Q. An aqueous solution of NaCl on electrolysis gives

H_{2} (g), C l_{2} (g)

and

N a O H

according to the reaction :

2 C l^{-} (a q) + 2 H_{2} O (l) ⟶ 2 O H^{-} (a q) + H_{2} (g) + C l_{2} (g)

A direct current of 25 amperes with a current efficiency of 62% is passed. Calculate the time required to produce 1 kg

C l_{2} (g)

Q. For the reactions (i)

H_{2} (g) + C l_{2} (g) ⟶ 2 H C l (g) + x K J

(ii)

H_{2} (g) + C l_{2} (g) ⟶ 2 H C l (l) + y K J

Which of the following statements is correct?

Q. Complete the following reaction:

2 NaOH (aq) + H_{2} {SO}_{4} (aq) \to

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