Identify the correct sequence of electron transfer in z -scheme of light reaction

e^{-} A c c e p t o r \to E T S \to P S I I \to N A D P^{+} \to P S I \to e^{-} A c c e p t o r

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P S I I \to e^{-} A c c e p t o r \to E T S \to P S I \to e^{-} A c c e p t o r \to N A D P^{+}

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E T S \to P S I \to e^{-} A c c e p t o r \to P S I I \to e^{-} A c c e p t o r \to N A D P^{+}

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e^{-} A c c e p t o r \to P S I \to P S I I \to e^{-} A c c e p t o r \to E T S \to N A D P^{+}

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Solution

The correct option is B $P S I I \to e^{-} A c c e p t o r \to E T S \to P S I \to e^{-} A c c e p t o r \to N A D P^{+}$
In z - scheme, PSII is excited first and releases an electron. This electron is accepted by an $e^{-}$ acceptor, plastoquinone and passed to the electron transport system (ETS) and then to plastocyanin which transfers electrons to PSI. PSI excites and releases electron which is finally accepted by $N A D P^{+}$ through ferredoxin.

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