Identify the correct set:

Molecule
Hybridization
Shape
Number of lone pairs of electrons
$(1)$
$X e O_{3}$
$s p^{3}$
pyramidal
$1$
$(2)$
$X e F_{4}$ $s p^{3} d^{2}$ planar $3$
$(3)$
$X e F_{2}$
$s p^{3} d$
linear
$2$
$(4)$
$X e O_{4}$
$s p^{3} d^{2}$
pyramidal
$1$

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Solution

The correct option is A 1

$X e O_{3}$ has $6$ bonds attached to oxygen and one lone pair left as $X e$ has $8$ electrons in its outermost shell.

The hybridization is $s p^{3}$ as it has $3$ sigma bonds and one lone pair. The shape is also pyramidal.

Hence, the correct answer is option $A$ .

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	Molecule	Hybridization	Shape	Number of lone pairs of electrons
$(1)$	$X e O_{3}$	$s p^{3}$	pyramidal	$1$
$(2)$	$X e F_{4}$	$s p^{3} d^{2}$	planar	$3$
$(3)$	$X e F_{2}$	$s p^{3} d$	linear	$2$
$(4)$	$X e O_{4}$	$s p^{3} d^{2}$	pyramidal	$1$