\(5 \div \dfrac{1}{3}=5\times \dfrac{3}{1} =15 \\ \)
\(\dfrac{1}{6} \div 2=\dfrac{1}{6} \div\dfrac{2}{1}=\dfrac{1}{6}\times \dfrac{1}{2}=\dfrac{1}{12} \\ \)
\(\dfrac{1}{4} \div 3=\dfrac{1}{4} \div\dfrac{3}{1}=\dfrac{1}{4}\times \dfrac{1}{3}=\dfrac{1}{14} \)
We can see that,
\(⇒ [5 ÷ \dfrac{1}{3} ]\) is greater than \([\dfrac{1}{6} ÷ 2]. \\ \)
\(⇒ [\dfrac{1}{6} ÷ 2]\) is equal to \([\dfrac{1}{4} ÷ 3]. \\\)
Therefore, statements P and S are correct.