The correct options are
A There are two bridging hydrogen atoms.
B Each boron atom forms four bonds
C All hydrogen atoms are not in same plane
D Each boron atom is in
sp3 hybridized state
a)
BH3 dimerizes to give diborane
(B2H6), in which two hydrogen atoms are bridged and four hydrogen atoms are terminal.
b) On dimerization, each boron atom is bonded with two terminal and two bridged hydrigen atoms i.e each has a steric number of 4. Hence both borons in
B2H6 are
sp3 hybridised.
c) In
B2H6, two borons and four terminal hydrogens lie in same plane, while bridged hydrogen atoms lie above and below the plane.
d)The dimerized
BH3 has four sigma bonds. Hence steric number of
B is four. So each boron in diborane is
sp3 hybridized.