The correct options are
B Wave nature of the running train is difficult to obseve because wavelength is extremely small
D If an electron is accelerated through 20 V potential difference, if it has already 5 eV kinetic energy then wavelength of the electron is approximately √6 oA
(A) λ can be calculated as: λ=hmv=6.626×10−341×100=6.626×10−36 m.
λ comes out to be very small.
(B) Heisenberg's principle is applicable for microscopic objects. So, wave nature of the running train is difficult to observe because wavelength is extremely small.
(C) de-Broglie wavelength associated with electron can be calculated by using λ=hmv.
(D)KEf=5+20=25 eV
∴λ=√150KEf=√15025=√6 oA