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Question

Identify the correct trend given below :
(Atomic No. of Ti = 22, Cr = 24 and Mo = 42)

A
Δo of [Cr(H2O)6]2+>[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+>[Ti(H2O)6]2+
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B
Δo of [Cr(H2O)6]2+<[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+<[Ti(H2O)6]2+
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C
Δo of [Cr(H2O)6]2+<[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+>[Ti(H2O)6]2+
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D
Δo of [Cr(H2O)6]2+>[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+>[Ti(H2O)6]2+
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Solution

The correct option is A Δo of [Cr(H2O)6]2+>[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+>[Ti(H2O)6]2+

The crystal field splitting energy, ΔoCharge on metal ionsize of metal ion

Considering both the factors we get-

Δo of [Cr(H2O)6]2+>[Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+>[Ti(H2O)6]2+

Hence, the correct option is (A)


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