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Multi-Electron Configurations and Orbital Diagrams

Identify the ...

Question

Identify the element for which electronic configuration in $+ 3$ oxidation state is $[A r] 3 d^{5} :$

JEE MAINS 2021

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Solution

$M n (25) = [A r] 3 d^{5} 4 s^{2}$

$M n^{+ 3} = [A r] 3 d^{4} 4 s^{0}$

$R u - belongs to 4d$ transition series

$C o (27) = [A r] 3 d^{7} 4 s^{2}$

$C o^{+ 3} = [A r] 3 d^{6} 4 s^{0}$

$F e (26) = [A r] 3 d^{6} 4 s^{2}$

$F e^{+ 3} = [A r] 3 d^{5} 4 s^{0}$

Hence, option (d) is correct.

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