You visited us 1 times! Enjoying our articles? Unlock Full Access!

Transposing Method

Identify the ...

Question

Identify the equations below, which has no solution?

\frac{3}{8} (x - 2) = \frac{8}{3} (x + 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{3}{2} (2 x - 8) = 3 x - 12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 (\frac{3}{4} x + 5) = 3 x + 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 (\frac{2}{3} x + 5) = 4 x + 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $6 (\frac{2}{3} x + 5) = 4 x + 5$
(A) $\frac{3}{8} (x - 2) = \frac{8}{3} (x + 2)$
$\Rightarrow 9 (x - 2) = 64 (x + 2)$
$\Rightarrow 9 x - 18 = 64 x + 128$
$\Rightarrow 9 x - 64 x = 128 + 18$
$\Rightarrow - 55 x = 146$
$\Rightarrow x = \frac{- 146}{55}$

(B) $- \frac{3}{2} (2 x - 8) = 3 x - 12$
$\Rightarrow - 3 (2 x - 8) = 6 x - 24$
$\Rightarrow - 6 x + 24 = 6 x + 24$
$\Rightarrow - 6 x - 6 x = - 24 - 24$
$\Rightarrow - 12 x = - 48$
$\Rightarrow x = 4$

(C) $(\frac{3}{4} x + 5) = 2 x + 20$
$\Rightarrow 3 x + 5 = 2 x + 20$
$\Rightarrow 3 x - 2 x = 20 - 5$
$\Rightarrow x = 15$

(D) $6 (\frac{2}{3} x + 5) = (4 x + 5)$
$\Rightarrow \frac{12 x}{3} x + 30 = 4 x + 5$
$\Rightarrow 4 x + 30 = 4 x + 5$
$4 x - 4 x = 5 - 30$ this is not possible

In these equation A,B,C, has solution
But equation D has no solution

Suggest Corrections

Similar questions

4 x^{5} + 7 x^{4} + 14 x^{3} + 3 x^{2} - 8 x + 6

x^{2} + 3 x + 2

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

2

x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

4^{x} + 2^{2 x - 1} = 3^{x + \frac{1}{2}} + 3^{x - \frac{1}{2}}

x =

∣ ∣ ∣ ∣ \begin{matrix} x + 2 & 2 x + 3 & 3 x + 4 2 x + 3 & 3 x + 4 & 4 x + 5 3 x + 5 & 5 x + 8 & 10 x + 17 \end{matrix} ∣ ∣ ∣ ∣ = 0

Join BYJU'S Learning Program