Identify the false statement.
∼(p ∨∼q)=∼p ∧ q
∼(p ∨ q)=∼p ∨∼q
(p ∧ q)∧∼p is a contradiction
(p ∨ q)∨∼p is a tautology
∼(p ∧ q)=∼p ∧∼q Hence option B is false.