Identify the following reaction as either oxidation or reduction:
$Z n \to Z n^{+ 2} + 2 e^{-}$

Open in App

Solution

Oxidation is the $loss of electrons$ or an increase in the oxidation state of an atom, an ion, or of certain atoms in a molecule.
Reduction is the gain of electrons or a decrease in the oxidation state of an atom, an ion, or of certain atoms in a molecule
in this given reaction ( $Z n \to Z n^{2 +} + 2 e^{-})$ , there is the loss of electrons thus, this is the oxidation reaction.

Suggest Corrections

Similar questions

Z n \to Z n^{+ +} + 2 e^{-}, E^{0} = 0.76 V

C u \to C u^{+ +} + 2 e^{-}, E^{0} = 0.34 V

Identify the following reaction as either oxidation or reduction:

$Zn \to {Zn}^{+ 2} + 2 e^{-}$

Identify the following reactions as either oxidation or reduction:

(i) O + 2e^-⇢ O^2-

Z n (s) + P b {C l}_{2} (a q) ⟶ P b (s) + Z n {C l}_{2} (a q)

Z n (s) ⟶ {Z n}^{2 +} (a q) + 2 e^{-}

{P b}^{2 +} (a q) + 2 e^{-} ⟶ P b (s)

P b^{2} +

Z n^{2}

^{+}

Join BYJU'S Learning Program