Identify the graph type and calculate speed from the graph.

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Solution

The graph is a linear straight line, so we can say it is a uniform motion graph.
$F r o m t h e g r a p h, S p e e d = \frac{f i n a l p o s i t i o n - i n i t i a l p o s i t i o n}{e n d t i m e - s t a r t t i m e} = \frac{(50 - 0)}{(5 - 0)} = \frac{50}{5} = 10 m / s$

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Identify the graph type and calculate speed from the graph.

The graph is a linear straight line, so we can say it is a uniform motion graph. From the graph, Speed = final position − initial positionend time − start time = (50 − 0)(5 − 0) = 505 = 10 m/s

The graph is a linear straight line, so we can say it is a uniform motion graph.
$F r o m t h e g r a p h, S p e e d = \frac{f i n a l p o s i t i o n - i n i t i a l p o s i t i o n}{e n d t i m e - s t a r t t i m e} = \frac{(50 - 0)}{(5 - 0)} = \frac{50}{5} = 10 m / s$