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Question

Identify the incorrect statement from the options below for the given cell:


A

If Eext = 1.1 V, no flow of e– or current occurs

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B

If Eext > 1.1 V, Zn dissolves at the Zn electrode and Cu deposits at the Cu electrode

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C

If Eext > 1.1 V, e- flow from Cu to Zn

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D

If Eext < 1.1 V, Zn dissolves at the anode and Cu deposits at the cathode

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Solution

The correct option is B

If Eext > 1.1 V, Zn dissolves at the Zn electrode and Cu deposits at the Cu electrode


Explanation for the correct option:

The correct option is (B)

IfEext>1.1V,ZndissolvesatZnelectrodeandCudepositsatCuelectrode.Ecell°=0.34-(-0.76)=1.10voltIfEext>1.10voltCuAnodeZnCathodeIfEext=1.10voltZnAnodeCuCathode

If Eext > 1.1 V, Zn dissolves at the Zn electrode, and Cu deposits at the Cu electrode.

If Eext > 1.1 V, Electron will flow from Cu to Zn, zinc will be deposited on the zinc electrode and copper will dissolve from the copper electrode.

Explanation For the Wrong Option:

(a) If Eext = 1.1 V, no flow of e- or current occurs.

If we supply 1.1v from outside and inside also we have 1.1v, so no current will flow.

(c) If Eext > 1.1 V, e- flow from Cu to Zn

If Eext > 1.1 V, Electron will flow from Cu to Zn, zinc will be deposited on the zinc electrode and copper will dissolve from the copper electrode.

We know Ecell value is 1.1v so if we put more than 1.1v then the current will flow from Cu to Zn.

(d) If Eext < 1.1 V, Zn dissolves at the anode, and Cu deposits at the cathode.

If we put less than 1.1v then Zn will dissolve and Cu deposits.

Final Answer: Hence, option (B) is correct. If Eext > 1.1 V, Zn dissolves at the Zn electrode, and Cu deposits at the Cu electrode.


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