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Question

Identify the missing numbers in the given pattern and also find the rule behind it.
1242124212(i)21(ii)42(iii)24(iv)12421242

A
(i)4(ii)2(iii)1(iv)2,ABCB
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B
(i)4(ii)2(iii)1(iv)1,ABBC
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C
(i)2(ii)2(iii)2(iv)2,ABCC
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D
(i)4(ii)2(iii)1(iv)2,AABC
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Solution

The correct option is A (i)4(ii)2(iii)1(iv)2,ABCB
Let us denote 1 with A, 2 with B, and 4 with C.
So, 1242 becomes ABCB.
The complete pattern following the rule ABCB will be:
1 2 4 2 1 2 4 2 1 2 4 2 1 2 4 2 1 2 4 2 1 2 4 2 1 2 4 2
ABCBABCBABCBABCBABCBABCBABCB

The missing links are (i)4(ii)2(iii)1(iv)2.
So, Option D is the correct answer.

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