Question

Identify the missing numbers in the given pattern and also find the rule behind it.
$2245224522\left(i\right)52\left(ii\right)45\left(iii\right)24\left(iv\right)22452245$

• A. (i) 4~ (ii) 4 ~(iii) 2 ~(iv) 5, ABCC
• B. $\left(i\right)4\left(ii\right)2\left(iii\right)4\left(iv\right)5,ABCA$
• C. (i) 2 ~(ii) 2 ~(iii) 2~ (iv) 5, ABBC
• D. (i) 4~ (ii) 2 ~(iii) 2 ~(iv) 5, AABC

Answer 1

The correct option is D (i) 4~ (ii) 2 ~(iii) 2 ~(iv) 5, AABC

Let us denote $2$ with $A,4$ with $B,$ and $5$ with $C$.
So, $2245$ becomes $AABC.$
The complete pattern following the rule $AABC$ will be:

$2245224522452245224522452245$
$AABCAABCAABCAABCAABCAABCAABC$
The missing links are $\left(i\right)4\left(ii\right)2\left(iii\right)2\left(iv\right)5.$
So, Option B is the correct answer.