Identify the outlier in each data set. Then find the mean, median, and mode of the data set when the outlier is included and when it is not.
16. 947 757 103 619 661 582 626 900 869 728 1001 596 515

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Solution

Dear student
$16) E x t r e m e l y l o w v a l u e = 103 E x t r e m e l y h i g h v a l u e = 1001 M e a n, m e d i a n a n d m o d e i n c l u d i n g o u t l i e r M e a n = \frac{S u m o f n u m b e r s}{T o t a l n o . o f n u m b e r s} = \frac{947 + 757 + 103 + 619 + 661 + 582 + 626 + 900 + 869 + 728 + 1001 + 596 + 515}{13} = \frac{8243}{13} = 634.08 M e d i a n A r r a n g e t h e d a t a i n i n c r e a \sin g o r d e r 103 515 582 596 619 626 661 728 757 869 900 947 1001 H e r e 661 i s t h e m i d d l e n u m b e r i n t h e d a t a . S o, M e d i a n = 661 M o d e : N o m o d e \sin c e n o n u m b e r i s r e p e a t i n g . S i m i l a r l y f i n d o t h e r .$
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