wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

Identify the oxidant and the reductant in the following reaction respectively:
I2+Na2S2O3Na2S4O6+NaI

A
I2 & Na2S2O3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Na2S2O3 & I2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
I2 & NaI
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
NaI & I2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A I2 & Na2S2O3
(0)I2+(+2)Na2S2O3(+2.5)Na2S4O6+(1)NaI.
(0)I2(oxidant)(1)NaI(reduction half).
(+2)Na2S2O3(reductant)(2.5)Na2S4O6(oxidation half).

A species which gain electron in a redox reaction is called as oxidising agent.
(I2) gets converted into nitric oxide (I). Iodine is getting reduced because it is gaining electrons, so I2 is the oxidizing agent.

A species which looses electron in a redox reaction is called as reducing agent.
Na2S2O3 gets converted to Na2S4O6 Na2S2O3 is getting oxidized since there is loss of electrons , so it is the reducing agent.

I2 and Na2S2O3 in this order is the correct answer.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon