Question

Identify the oxidation states of titanium $(Z=22)$ and copper $(Z=29)$ in their colourless compounds:

• A. $T{i}^{3+},C{u}^{2+}$
• B. $T{i}^{2+},C{u}^{2+}$
• C. $T{i}^{4+},C{u}^{+}$
• D. $T{i}^{4+},C{u}^{2+}$

Answer 1

Answer: (C)

$T{i}^{4+},C{u}^{+}$

The oxidation states of titanium $(Z=22)$ and copper $(Z=29)$ in their colourless compounds are $T{i}^{4+},C{u}^{+}$ respectively.

The electronic configurations are given below.

$Ti:\left[Ar\right]4s^{2}3d^2$
$T{i}^{4+}:\left[Ar\right]4s^{0}3d^0$

$Cu:\left[Ar\right]4s^{1}3d^{10}$
$C{u}^{+}:\left[Ar\right]4s^{0}3d^{10}$

The above electronic configurations of ions correspond to zero unpaired electrons.