Identify the oxidising agent and the reducing agent in the following redox reaction:

$7 {C N}^{-} + 2 {O H}^{-} + 2 C u {({N H}_{3})}_{4}^{2 +} ⟶ 2 C u {(C N)}_{3}^{2 -} + 8 {N H}_{3} + C {N O}^{-} + H_{2} O$

Oxidising agent:

C u {({N H}_{3})}_{4}^{2 +}

; Reducing agent:

{C N O}^{-}

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Oxidising agent:

C u {({N H}_{3})}_{4}^{2 +}

; Reducing agent:

{C N}^{-}

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Oxidising agent:

{C N O}^{-}

; Reducing agent:

{C N}^{-}

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None of these

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Solution

The correct option is C Oxidising agent: $C u {({N H}_{3})}_{4}^{2 +}$ ; Reducing agent: ${C N}^{-}$
The redox reaction :

$7 {C N}^{-} + 2 {O H}^{-} + 2 C u {({N H}_{3})}_{4}^{2 +} ⟶ 2 C u {(C N)}_{3}^{2 -} + 8 {N H}_{3} + C {N O}^{-} + H_{2} O$ .
The oxidation number of Cu decreases from +2 to +1.
Thus, chlorine is reduced.
Hence, $C u {({N H}_{3})}_{4}^{2 +}$ acts as oxidizing agent.
The oxidation number of CN group increases from -1 to +1. Thus, CN is oxidized.
Hence, ${C N}^{-}$ acts as reducing agent.
The correct option is B.

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Question 6

Consider the reactions

(i) $H_{2} O_{2} + 2 H I \to I_{2} + 2 H_{2} O$
(ii) $H O C l + H_{2} O_{2} \to H_{3} O^{+} C l^{-} + O_{2}$

Which of the following statements is correct about $H_{2} O_{2}$ with reference to these reactions? Hydrogen peroxide is ........

(a) an oxidising agent in both (i) and (ii)

(b) an oxidising agent in (i) and reducing agent in (ii)

(d) a reducing agent in both (i) and (ii)

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