Identify the oxidizing agent and the reducing agent in the following redox reaction :

${M n O}_{4}^{-} + S O_{3}^{2 -} \to M n^{2 +} + S O_{4}^{2 -}$

oxidizing agents

M n O_{4}^{-}

; reducing agent is

S O_{3}^{2 -}

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oxidizing agents

S O_{3}^{2 -}

; reducing agent is

M n O_{4}^{-}

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can't be predicted

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none of the above

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Solution

The correct option is B oxidizing agents $M n O_{4}^{-}$ ; reducing agent is $S O_{3}^{2 -}$
In the given reaction, the oxidation number of $M n$ decreases from $+ 7$ in the reactant to $+ 2$ in the product. Hence, it is being reduced or simply, $M n O_{4}^{-}$ is the oxidizing agent

Similarly, the oxidation number of $S$ increases from $+ 4$ in the reactant to $+ 6$ in the product. Hence, it is being oxidized or simply, $S O_{3}^{2 -}$ is the reducing agent

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