Identify the oxidizing agent and the reducing agent in the reaction given below:
Hydrogen sulphide + Bromine→ Hydrogen bromide + Sulphur

Hydrogen sulphide: Reducing agent
Bromine: Oxidizing agent.

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Hydrogen sulphide: Oxidizing agent
Bromine: Reducing agent.

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The given reaction is a double displacement reaction.

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None of these

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Solution

The correct option is A Hydrogen sulphide: Reducing agent
Bromine: Oxidizing agent.
Reducing agent is the substance that gives away its hydrogen atoms. Oxidizing agent is the substance that accepts the hydrogen atoms.

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Similar questions

Identify the substance oxidized, substance reduced, oxidizing agent and reducing agent in the given reaction
$H_{2} S + B r_{2} \to 2 H B r + S$

Identify the oxidizing agent and the reducing agent in the reaction given below:

$H_{2} S (g) + B r_{2} (l) \to 2 H B r (a q) + S (s)$

When the gases sulphur dioxide and hydrogen sulphide mix in the presence of water the reaction is :

SO₂+2H₂S=2H₂O+3S

Here hydrogen sulphide is acting as :

A. Oxidizing agent

B. Reducing agent

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