1
Question
Identify the pair of alkanes which can exhibit chain isomerism and has a neo isomer respectively?
Identify the pair of alkanes which can exhibit chain isomerism and has a neo isomer respectively?
Open in App
Solution
The correct options are
B C5H12,C6H14
C C4H10,C5H12
D C6H14,C7H16
Option (A) propane; C3H8 does not show isomerism, butane; C4H10 does not have a neo isomer.
Option (B) C4H10 & C5H12
Butane exists as n-butane; CH3−CH2−CH2−CH3 and iso-butane; CH3−CH(CH3)−CH3
Pentane exists as neo-pentane as; C(CH3)4
Option (C) C5H12 & C6H14
Pentane exists as n-pentane; CH3−CH2−CH2−CH2−CH3, iso-pentane; CH3−CH(CH3)−CH2−CH3 and neo-pentane; C(CH3)4
Hexane exists as neo-hexane as; (CH3)3−C−C2H5
Option (D) C6H14 & C7H16
Hexane exists has five structural isomers which exist in form of n-hexane; CH3−CH2−CH2−CH2−CH2−CH3, iso-hexane; CH3−CH(CH3)−CH2−CH2−CH3 and neo-hexane; (CH3)3−C−C2H5.
Heptane exists as neo-heptane as; (CH3)3−C−C3H7.
B C5H12,C6H14
C C4H10,C5H12
D C6H14,C7H16
Option (A) propane; C3H8 does not show isomerism, butane; C4H10 does not have a neo isomer.
Option (B) C4H10 & C5H12Butane exists as n-butane; CH3−CH2−CH2−CH3 and iso-butane; CH3−CH(CH3)−CH3
Pentane exists as neo-pentane as; C(CH3)4
Option (C) C5H12 & C6H14
Pentane exists as n-pentane; CH3−CH2−CH2−CH2−CH3, iso-pentane; CH3−CH(CH3)−CH2−CH3 and neo-pentane; C(CH3)4
Hexane exists as neo-hexane as; (CH3)3−C−C2H5
Option (D) C6H14 & C7H16
Hexane exists has five structural isomers which exist in form of n-hexane; CH3−CH2−CH2−CH2−CH2−CH3, iso-hexane; CH3−CH(CH3)−CH2−CH2−CH3 and neo-hexane; (CH3)3−C−C2H5.
Heptane exists as neo-heptane as; (CH3)3−C−C3H7.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
