Identify the pair of gases that have equal rates of diffusion.

N O, C O

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N_{2} O_{2}, C O

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N_{2} O, C O_{2}

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C O_{2}, N O_{2}

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Solution

The correct option is C $N_{2} O, C O_{2}$
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

Molecular mass of $N_{2} O = 28 + 16 = 44$

Molecular mass of $C O_{2} = 12 + 32 = 44$

$\frac{r_{N_{2} O}}{r_{C O_{2}}} = 1, r_{N_{2} O} = r_{C O_{2}}$

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