Question

Identify the pairs of equivalent rational numbers.

$\frac{-2}{3},\frac{16}{-24}$

Answer 1

Two rational numbers are said to be equal when their standard forms are equal.

$\frac{-2}{3}=\frac{-2}{3}=\frac{-2}{3}$

and

$$\begin{gathered} \Rightarrow \frac{16}{-24}=\frac{16\times \left(-1\right)}{-24\times \left(-1\right)}=\frac{-16}{24} \\ \Rightarrow \frac{-16}{24}=\frac{-2\times 8}{3\times 8}=\frac{-2}{3} \end{gathered}$$

Since, $\frac{-2}{3}$ = $\frac{-2}{3}$

Hence, $\frac{-2}{3}$ and $\frac{16}{-24}$ are equivalent.