Question

Identify the position where electrophilic aromatic substitution (EAS) is most favourable.

• A. A
• B. B
• C. C
• D. Both A and C

Answer 1

The correct option is B B

As the electron density increases on the ring, the rate of electrophilic substitution increases. $-NH-\stackrel{\underset{||}{O}}{C}-C{H}_3$ is electron donating by $+M$ effect and $-C{H}_3$ group is electron donating by hyperconjugation and $+I$ effect.
Since, electron donating groups are $o-$ and $p-$directing hence due to high electron donating power of $-NH-\stackrel{\underset{||}{O}}{C}-C{H}_3$ group, electrophilic substitution will be favoured at B position.