Question

Identify the product D in the following series of reaction

$C{H}_{3}COOH\stackrel{LiAl{H}_4}{\to }A\underset{443K}{\overset{H^{+}}{\to }}B\stackrel{B{r}_2}{\to }C\underset{KOH}{\overset{alc.}{\to }}D$

• A. Methane
• B. Alcohol
• C. Acetylene
• D. Benzaldehyde

Answer 1

The correct option is C

Acetylene

$C{H}_{3}COOH\stackrel{LiAl{H}_4}{\to }C{H}_3-C{H}_2-OH\underset{443K}{\overset{H^{+}}{\to }}$
$C{H}_2=C{H}_2\stackrel{B{r}_2}{\to }C{H}_2-C{H}_2\underset{KOH}{\overset{alc.}{\to }}$
$||$
$BrBr$

$CH\equiv CH+2KBr+2H_{2}O$
$\text{Acetylene}$