No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D C2H5OH is a weak nucleophile and the substrate is bulky so it favours SN1 reaction.
Neopentyl bromide forms 1° carbocation which rearranges to form the more stable 3° carbocation. This is attacked by weak nucleophile ethanol followed by loss of proton to yield ethyl tert-pentyl ether.