Identify the product of the following reaction.
$C l C H_{2} C H_{2} C H_{2} B r + K C N \to P r o d u c t$

C l C H_{2} C H_{2} C H_{2} C N

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C N C H_{2} C H_{2} B r

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C N C H_{2} C H_{2} C H_{2} C N

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C H_{3} C H_{2} C H_{2} B r

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Solution

The correct option is A $C l C H_{2} C H_{2} C H_{2} C N$
The IUPAC name of the compound $C l C H_{2} C H_{2} C H_{2} B r$ is 1-Bromo-3-chloropropane. When 1-Bromo-3-chloropropane reacts with $K C N$ i.e potassium cyanide, the product formed is:
$C l C H_{2} C H_{2} C H_{2} B r + K C N ⟶ C l C H_{2} C H_{2} C H_{2} C N + K B r$

[Note: $B r^{-}$ is better-leaving group than $C l^{-}$ .]

Therefore A is the correct option.

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