Identify the product $“ Z ”$ in the following series of reactions:

Hexanoic acid

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α

-methyl caproic acid

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Heptanoic acid

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None of these

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Solution

The correct option is C Heptanoic acid
We know that glucose is an aldohexose. Glucose reacts with HCN to give a cynohydrin at the aldehyde group (X). When this cyanohydrin is hydrolysed, we get an acid at the nitrile position(Y). When this is reduced by using HI/heat, we get heptanoic acid.
$C H O - (C H O H)_{4} - C H_{2} O H + H C N ⟶ C H (C N) O H - (C H O H)_{4} - C H_{2} O H (c y a n o h y d r i n - X)$

$C H (C N) O H - (C H O H)_{4} - C H_{2} O H + H_{2} O ⟶ C O O H - (C H O H)_{5} - C H_{2} O H (Y)$

$C O O H - (C H O H)_{5} - C H_{2} O H + H I ⟶ C O O H - (C H_{2})_{5} - C H_{3} (h e p t a n o i c a c i d - Z)$

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Identify the product D in the following series of reaction

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