Identify the products of the following reaction:
Methyl alcohol + Ethyl magnesium bromide = ?

C H_{4}

and

C H_{3} O M g B r

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C H_{4}

and

C H_{3} C H_{2} O M g B r

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C_{2} H_{6}

and

C H_{3} O M g B r

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C_{2} H_{6}

and

C H_{3} C H_{2} O M g B r

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Solution

The correct option is C $C_{2} H_{6}$ and $C H_{3} O M g B r$
Alcohols reacts with Grignard reagents to form hydrocarbons. Also, the alkane formed from this reaction corresponds to the alkyl group of the Grignard reagent and not the alcohol.
$C H_{3} O H + C H_{3} C H_{2} M g B r \to C H_{3} C H_{3} + C H_{3} O M g B r$

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