Identify the reactions accompanied by the formation of $11 g o f C O_{2}$ gas:

100 g o f 50 % p u r e C a C O_{3}

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100 g o f 25 % p u r e C a C O_{3}

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42 g o f 50 %

p u r e N a H C O_{3}

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84 g o f 50 %

p u r e N a H C O_{3}

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Solution

The correct options are
B $100 g o f 25 % p u r e C a C O_{3}$
D $84 g o f 50 %$ $p u r e N a H C O_{3}$
Molecular weight of $C O_{2}$ is 44 g. Therefore 11 g corresponds to 0.25 moles.
1 mole of 50% $C a C O_{3}$ is 100g which produces 0.5 moles of carbon dioxide gas i.e. 22g of $C O_{2}$
1 mole of 25% $C a C O_{3}$ is 100g which produces 0.25 moles of carbon dioxide gas i.e. 11g of $C O_{2}$
1 mole of $N a H C O_{3}$ corresponds to 84 g, which produces 0.5 mole or 22 g of $C O_{2}$ gas. But same amount of 50% purity produces 0.25 mole or 11 g $C O_{2} .$
$2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}$
Therefore, option B and D are correct

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