Identify the set of reagent /reaction conditions $^{'} X^{'}$ and $^{'} Y^{'}$ in the following set of transformations.
$C H_{3} C H_{2} - C H_{2} B r X - \to p r o d u c t Y \to C H_{3} - C | B r H - C H_{3}$ .

X =

concentrated alcoholic

N a O H, 80^{\circ} C, Y = H B r / C H_{3} C O O H, 20^{\circ} C

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X = d i l . a q N a O H, 20^{\circ} C, Y = H B r / C H_{3} C O O H, 20^{\circ} C

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X = d i l . a q N a O H, 20^{\circ} C, Y = B r_{2} / C H C l_{3}, 0^{\circ} C

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X = c o n c e n t r a t e d N a O H, 80^{\circ} C, Y = B r_{2} / C H C l_{3}, 0^{\circ} C

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Solution

The correct option is B $X =$ concentrated alcoholic $N a O H, 80^{\circ} C, Y = H B r / C H_{3} C O O H, 20^{\circ} C$
The dehydrohalogenation of 1-bromo propane with alco. $N a O H$ or $K O H$ gives propene which on again hydrohalogenation with $H B r$ gives 2-bromopropane due to addition of Markonikoves rule for addition.

${C H}_{3} {C H}_{2} {C H}_{2} B r 80^{o} C - ---------- \to a l c . N a O H / K O H {C H}_{3} C H = {C H}_{2} H B r - -- \to {C H}_{3} C H B r {C H}_{3}$

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Similar questions

C H_{3} - C H_{2} - C H_{2} B r X - \to P r o d u c t Y \to C H_{3} - C | B r H - C H_{3}

(C H_{3})_{3} C C H = C H_{2} X - - \to T H F Y N a B H_{4} - --- \to N a O H (C H_{3})_{3} - C | O H - C H - C H_{3}

C H_{3} - C H_{2} - C H_{2} B r X - \to P r o d u c t Y \to C H_{3} - C | B r H - C H_{3}

The correct functional group X and the reagent/ reaction conditions Y in the following scheme are

C H_{3} C O O H \frac{N a O H}{H e a t} X N a O H, C a O - ------ \to Y; Y

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