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Preparation of Haloalkane from Alkene

Identify the ...

Question

Identify the set of reagent/reaction conditions ‘X’ and ‘Y’ in the following set of transformations:
$C H_{3} - C H_{2} - C H_{2} B r X - \to P r o d u c t Y \to C H_{3} - C | B r H - C H_{3}$

X = dilute aqueous NaOH,

20^{\circ} C

; Y = HBr/acetic acid,

20^{\circ} C

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X = concentrated alcoholic NaOH,

80^{\circ} C

; Y = HBr/acetic acid,

20^{\circ} C

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X = dilute aqueous NaOH,

20^{\circ} C

;

Y = \frac{B r_{2}}{C H C l_{3}}

0^{\circ} C

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X = concentrated alcoholic NaOH,

80^{\circ} C

;

Y = \frac{B r_{2}}{C H C l_{3}}

0^{\circ} C

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Solution

The correct option is B X = concentrated alcoholic NaOH, $80^{\circ} C$ ; Y = HBr/acetic acid, $20^{\circ} C$

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^{'} X^{'}

^{'} Y^{'}

C H_{3} C H_{2} - C H_{2} B r X - \to p r o d u c t Y \to C H_{3} - C | B r H - C H_{3}

C H_{3} - C H_{2} - C H_{2} B r X - \to P r o d u c t Y \to C H_{3} - C | B r H - C H_{3}

C H_{3} - C H_{2} - C H = C H - C H_{3} + H C l \to X + Y

X

Y

C H_{3} C H_{2} C H_{2} I a l c . K O H - ---- \to X

C H_{3} - C H = C H_{2} Y \to

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