Identify the set of reagent/reaction conditions 'X' and 'Y' in the following set reaction:
A
X = dilute aqueous NaOH, 20∘C; Y = HBr/acetic acid, 20∘C
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B
X = concentrated alcoholic NaOH, 80∘C; Y = HBr/acetic acid, 20∘C
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C
X = dilute aqueous NaOH, 20∘C, Y = Br2/CHCl3,0∘C
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D
X = concentrated alcoholic NaOH, 80∘C;Y=Br2/CHCl3,0∘C
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Solution
The correct option is B X = concentrated alcoholic NaOH, 80∘C; Y = HBr/acetic acid, 20∘C
First dehydrohalogenation reaction proceed by reagent alc. NaOH forming propene and then by adding HBr, the addition of HBr proceeds by Markovnikov's rule.
Aqueous NaOH gives substitution products and alkene with Br2 gives disubstituted haloalkanes.
Hence, option (b) is correct.